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A stationary state is not the same thing as a standing wave.

The wave functions that come closest to the deBroglie picture are "circular orbitals", states with large principal quantum number $n$ and maximum value of angular momentum $\ell = n-1$. When then $m_\ell = \pm \ell$, the phase of the wave function varies only as a function of the angle in the plane of the orbital. Here an image for $n=6$ where phase is coded as color:

enter image description here

This is the time-independent part of the wave function. There are five deBroglie wavelengths around the circle, $\ell = 5.$ To get the time-dependent wave function, one multiplies with the phase factor $e^{iEt/\hbar}$.$e^{iEt/\hbar}.$ This adds a phase that grows with time, so that the colors rotate.

A standing wave would be a sum (or the difference) of the clockwise and the anti-clockwise pattern, $m_\ell = \ell$ and $m_\ell = - \ell$$m_\ell = - \ell.$

A stationary state is not the same thing as a standing wave.

The wave functions that come closest to the deBroglie picture are "circular orbitals", states with large principal quantum number $n$ and maximum value of angular momentum $\ell = n-1$. When then $m_\ell = \pm \ell$, the phase of the wave function varies only as a function of the angle in the plane of the orbital. Here an image for $n=6$ where phase is coded as color:

enter image description here

This is the time-independent part of the wave function. There are five deBroglie wavelengths around the circle, $\ell = 5.$ To get the time-dependent wave function, one multiplies with the phase factor $e^{iEt/\hbar}$. This adds a phase that grows with time, so that the colors rotate.

A standing wave would be a sum of the clockwise and the anti-clockwise pattern, $m_\ell = \ell$ and $m_\ell = - \ell$

A stationary state is not the same thing as a standing wave.

The wave functions that come closest to the deBroglie picture are "circular orbitals", states with large principal quantum number $n$ and maximum value of angular momentum $\ell = n-1$. When then $m_\ell = \pm \ell$, the phase of the wave function varies only as a function of the angle in the plane of the orbital. Here an image for $n=6$ where phase is coded as color:

enter image description here

This is the time-independent part of the wave function. There are five deBroglie wavelengths around the circle, $\ell = 5.$ To get the time-dependent wave function, one multiplies with the phase factor $e^{iEt/\hbar}.$ This adds a phase that grows with time, so that the colors rotate.

A standing wave would be a sum (or the difference) of the clockwise and the anti-clockwise pattern, $m_\ell = \ell$ and $m_\ell = - \ell.$

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user137289
user137289

A stationary state is not the same thing as a standing wave.

The wave function stat comfunctions that come closest to the deBroglie picture are "circular orbitals", states with large principal quantum number $n$, and maximum value of angular momentum $\ell$$\ell = n-1$. When then $m_\ell = \pm \ell$, the phase of the wave function varies only as a function of the angle in the plane of the orbital. Here an image for $n=6$ where phase is coded as color:

enter image description here

This is the time-independent part of the wave function. There are five deBroglie wavelengths around the circle, $\ell = 5.$ To get the time-dependent wave function, one multiplies with the phase factor $e^{iEt/\hbar}$. This adds a phase that grows with time, so that the colors rotate.

A standing wave would be a sum of the clockwise and the anti-clockwise pattern, $m_\ell = \ell$ and $m_\ell = - \ell$

A stationary state is not a standing wave.

The wave function stat com closest to the deBroglie picture are "circular orbitals", states with large principal quantum number $n$, maximum value of angular momentum $\ell$. When then $m_\ell = \pm \ell$, the phase of the wave function varies only as a function of the angle in the plane of the orbital. Here an image for $n=6$ where phase is coded as color:

enter image description here

This is the time-independent part of the wave function. To get the time-dependent wave function, one multiplies with the phase factor $e^{iEt/\hbar}$. This adds a phase that grows with time, so that the colors rotate.

A standing wave would be a sum of the clockwise and the anti-clockwise pattern, $m_\ell = \ell$ and $m_\ell = - \ell$

A stationary state is not the same thing as a standing wave.

The wave functions that come closest to the deBroglie picture are "circular orbitals", states with large principal quantum number $n$ and maximum value of angular momentum $\ell = n-1$. When then $m_\ell = \pm \ell$, the phase of the wave function varies only as a function of the angle in the plane of the orbital. Here an image for $n=6$ where phase is coded as color:

enter image description here

This is the time-independent part of the wave function. There are five deBroglie wavelengths around the circle, $\ell = 5.$ To get the time-dependent wave function, one multiplies with the phase factor $e^{iEt/\hbar}$. This adds a phase that grows with time, so that the colors rotate.

A standing wave would be a sum of the clockwise and the anti-clockwise pattern, $m_\ell = \ell$ and $m_\ell = - \ell$

Source Link
user137289
user137289

A stationary state is not a standing wave.

The wave function stat com closest to the deBroglie picture are "circular orbitals", states with large principal quantum number $n$, maximum value of angular momentum $\ell$. When then $m_\ell = \pm \ell$, the phase of the wave function varies only as a function of the angle in the plane of the orbital. Here an image for $n=6$ where phase is coded as color:

enter image description here

This is the time-independent part of the wave function. To get the time-dependent wave function, one multiplies with the phase factor $e^{iEt/\hbar}$. This adds a phase that grows with time, so that the colors rotate.

A standing wave would be a sum of the clockwise and the anti-clockwise pattern, $m_\ell = \ell$ and $m_\ell = - \ell$