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Jul 10, 2018 at 21:19 vote accept Sebastiano
Apr 1, 2018 at 0:19 history edited Raffaele d'Amelio CC BY-SA 3.0
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Mar 31, 2018 at 9:03 comment added Raffaele d'Amelio Sure, let's go one by one: 1) The potential is calculated simply integrating the electric field, you just need to be careful where you put the zero of your potential $V = -\int_0^{\infty}\vec{E}\cdot d\vec{r}$, in my case I choose the potential to be $0$ in the origin. 2) There was actually a mistake in my formula, I corrected it i hope it's clear now. 3)Check out this link tutorial.math.lamar.edu/Classes/CalcIII/EqnsOfPlanes.aspx Yes it is a scalar product. Grazie e buona pasqua anche a te :)
Mar 31, 2018 at 8:54 history edited Raffaele d'Amelio CC BY-SA 3.0
I fixed a mistake in the expression of $\hat{n}$.
Mar 30, 2018 at 20:26 comment added Sebastiano I give you my bounty also because you have had attention at my problem. 1) I have not understand because $V(x,y,z)=(V_1x,V_2y,V_3z)$; 2) If $\overline E=|E|\hat n$ why $\hat n = \ldots$? 3) Who is $\overline r$ (position vector) and $\overline r_0$? Can you put a figure please thus I understand better? After $\hat{n}\cdot\left(\vec{r}-\vec{r}_0\right)=0$, $\cdot$ is a scalar product? Can you explain better these details? Buona Pasqua e grazie.
Mar 30, 2018 at 20:16 history bounty ended Sebastiano
Mar 30, 2018 at 10:35 comment added Raffaele d'Amelio I edited my answer, I hope I made it better.
Mar 30, 2018 at 10:35 history edited Raffaele d'Amelio CC BY-SA 3.0
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Mar 29, 2018 at 19:26 comment added Sebastiano I modified my question again, hoping it would be clearer than before. I would like to understand how to find the general case and not the particular one. I thank you for your answer, which obviously vote positively, both for the effort and for the time you have dedicated to me.
Mar 29, 2018 at 13:06 review First posts
Mar 29, 2018 at 13:09
Mar 29, 2018 at 13:01 history answered Raffaele d'Amelio CC BY-SA 3.0