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Apr 17, 2018 at 5:52 comment added WillO @NorbertSchuch: Right. I meant, of course, to multiply, not to add, so the $+$ sign should be a $\times$. I could of course have been more succinct and just written $U\otimes V$, but preferred to write out the two factors $U\otimes 1$ and $1\otimes V$ to stress that each factor was the work of one experimenter.
Mar 30, 2018 at 13:51 comment added Norbert Schuch @WillO That's not a unitary operator.
Mar 27, 2018 at 21:59 review Suggested edits
Mar 27, 2018 at 22:41
Mar 27, 2018 at 18:58 answer added ostrichCamel timeline score: 4
Mar 27, 2018 at 18:46 answer added Panos C. timeline score: -4
Mar 27, 2018 at 18:26 comment added WillO The two-particle system is initially in a state of the form $x\otimes y$. What unitary operator do you plan to apply to bring it to an entangled state? Clearly operators of the form $U\otimes 1+1\otimes V$ won't do.
Mar 27, 2018 at 18:08 history asked Abhijeet Melkani CC BY-SA 3.0