Timeline for Laplace operator to find a bundle of parallel planes (equipotential surfaces) to two plates
Current License: CC BY-SA 3.0
21 events
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| Nov 27 at 22:58 | answer | added | Sebastiano | timeline score: 1 | |
| Jul 10, 2018 at 21:19 | vote | accept | Sebastiano | ||
| Mar 31, 2018 at 20:20 | history | edited | Sebastiano | CC BY-SA 3.0 |
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| S Mar 30, 2018 at 20:16 | history | bounty ended | Sebastiano | ||
| S Mar 30, 2018 at 20:16 | history | notice removed | Sebastiano | ||
| Mar 29, 2018 at 19:24 | history | edited | Sebastiano | CC BY-SA 3.0 |
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| Mar 29, 2018 at 13:01 | answer | added | Raffaele d'Amelio | timeline score: 1 | |
| Mar 26, 2018 at 21:33 | comment | added | Sebastiano | @Qmechanic I have added some details. I have not studied and resolved PDE when I was at university. | |
| Mar 26, 2018 at 21:31 | history | edited | Sebastiano | CC BY-SA 3.0 |
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| Mar 26, 2018 at 8:02 | history | edited | Sebastiano | CC BY-SA 3.0 |
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| Mar 25, 2018 at 21:26 | comment | added | Siva | @Sebastiano The perpendicularity follows almost by definition of "equipotential". Since equipotential surfaces have the same value of the potential, the gradient of the potential cannot have a nonzero component along the surface. That means the gradient must necessarily be normal to the equipotential surface. | |
| Mar 25, 2018 at 20:40 | history | tweeted | twitter.com/StackPhysics/status/978008857019641858 | ||
| Mar 25, 2018 at 20:28 | history | edited | Sebastiano |
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| S Mar 25, 2018 at 20:23 | history | bounty started | Sebastiano | ||
| S Mar 25, 2018 at 20:23 | history | notice added | Sebastiano | Canonical answer required | |
| Mar 21, 2018 at 22:37 | history | edited | Sebastiano | CC BY-SA 3.0 |
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| Mar 19, 2018 at 21:44 | comment | added | Sebastiano | @Qmechanic But Is there a mathematical proof of the your explanation? I would like to know if there is a mathematical demonstration like the one I reported. Namely, that for two parallel plates (in 3D) the equipotential surfaces turn out to be a bundle of parallel planes when the potential is changed from a higher to a lower one. I hope I have not asked a bad question because of the lack of attention I have had. Best regards. | |
| Mar 19, 2018 at 18:53 | comment | added | Qmechanic♦ | This seems to be merely the fact that the gradient is perpendicular to the equipotential surface. | |
| Mar 19, 2018 at 18:50 | history | edited | Qmechanic♦ |
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| Mar 19, 2018 at 18:42 | history | edited | Sebastiano |
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| Mar 19, 2018 at 11:46 | history | asked | Sebastiano | CC BY-SA 3.0 |