Timeline for Why does the sum of the voltage drops have to equal the voltage of the emf source?
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8 events
| when toggle format | what | by | license | comment | |
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| Nov 28, 2018 at 12:02 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Oct 28, 2018 at 9:00 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 29, 2018 at 14:21 | comment | added | Bill N | Even if you short a battery, there is an internal resistance which limits the current. | |
| Mar 16, 2018 at 3:30 | answer | added | Alfred Centauri | timeline score: 1 | |
| Mar 16, 2018 at 3:02 | review | Close votes | |||
| Apr 4, 2018 at 3:03 | |||||
| Mar 16, 2018 at 2:47 | comment | added | probably_someone | If you have no resistance, then you'll have shorted your battery, which isn't well-defined in circuit notation. In order to talk about things in the circuit model, you have to have at least some load between two terminals of a voltage source. | |
| Mar 16, 2018 at 2:43 | comment | added | sammy gerbil | Possible duplicate of I don't understand what we really mean by voltage drop | |
| Mar 16, 2018 at 2:31 | history | asked | Serendipitous Epiphany | CC BY-SA 3.0 |