Timeline for If a plane releases a ball flying completely vertically at 300m/s compared to completely horizontally, how will the kinetic energy be different?
Current License: CC BY-SA 3.0
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| Mar 7, 2018 at 2:29 | comment | added | dmckee --- ex-moderator kitten | @Aaron's comment is completely correct, but because $\vec{v}^2 = v_x^2 + v_y^2 + v_z^2$ it is possible to deal with a quantity you might call "the contribution to kinetic energy due to motion in the $x$ direction" (and $y$ and $z$ of course) in a manner that is not too silly. Such exercises are useful in making kinetic theory accessible to relatively unsophisticated audiences. But it should be emphasized that $\frac{1}{2}mv_x^2$ is not a "component of kinetic energy". See also: equipartition theorem. | |
| Mar 6, 2018 at 22:23 | answer | added | Allure | timeline score: 3 | |
| Mar 6, 2018 at 21:30 | answer | added | Polhode | timeline score: 2 | |
| Mar 6, 2018 at 21:23 | comment | added | BioPhysicist | Energy is not a vector quantity. You can't have vertical or horizontal kinetic energy. An object just has kinetic energy. | |
| Mar 6, 2018 at 21:10 | history | asked | Kevin Lee | CC BY-SA 3.0 |