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Oct 29, 2022 at 11:48 history edited glS CC BY-SA 4.0
edited title
Mar 14, 2018 at 3:43 answer added XXDD timeline score: -2
Mar 4, 2018 at 21:56 comment added gautampk The procedure puts the first entangled qubit and the qubit in the state $\psi$ in one of four states. It doesn't put the second entangled qubit in one of the four states.
Mar 4, 2018 at 21:39 history edited Chris CC BY-SA 3.0
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Mar 4, 2018 at 21:27 history edited Qmechanic
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Mar 4, 2018 at 20:27 vote accept bvkaradz
Mar 4, 2018 at 20:10 answer added alanf timeline score: 2
Mar 4, 2018 at 19:52 comment added Quantum spaghettification A diagram would help clarify what you are asking. In your last but one paragraph the 4 predetermined states do depend on $\psi$, so it doesn't really matter that you have a continuum of possibilities for $\psi$.
Mar 4, 2018 at 19:52 review First posts
Mar 4, 2018 at 21:36
Mar 4, 2018 at 19:46 history asked bvkaradz CC BY-SA 3.0