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Timeline for Why is Noether's theorem important?

Current License: CC BY-SA 4.0

11 events
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Aug 26, 2019 at 3:30 history edited user1379857 CC BY-SA 4.0
explained why initial conditions aren't conserved quantities
Feb 27, 2018 at 21:05 history edited user1379857 CC BY-SA 3.0
changed fermion to lepton and z to xy
Feb 26, 2018 at 22:37 comment added user1379857 For anyone else interested in details, $A$ does not actually need to be $0$ in order for the transformation to be a symmetry, $A$ need only be a total time derivative, say $A = \dot C$. In such a case, $B - C$ would then be the complete conserved quantity. A good example of this is time translations. Under a time translation $q \to q + \varepsilon \dot q$, our "$A$" would be $A = \dot L$, and $B - L$ turns out to be the energy.
Feb 26, 2018 at 22:29 comment added user1379857 Well, seeing as you can choose the variations $\varepsilon$, you can indeed impose that $\dot \varepsilon$ is small. Furthermore, another (perhaps slightly more rigorous way) to do calculus of variations is to take the variation in the path to be $\varepsilon \eta(t)$, where $\eta$ is not infinitessimal, and $\varepsilon$ is constant. As long as $\dot \eta$ is bounded above, $\varepsilon \dot \eta$ will shrink as $\varepsilon \to 0$.
Feb 26, 2018 at 22:21 comment added anderstood Why does $\varepsilon$ small imply $\dot\varepsilon$ small? Is it an assumption on $\varepsilon$?
Feb 26, 2018 at 11:14 vote accept Defcon97
S Feb 26, 2018 at 10:18 history suggested J. Manuel CC BY-SA 3.0
Added a dot to the q_i variables in the leftmost part of first equation
Feb 26, 2018 at 9:58 review Suggested edits
S Feb 26, 2018 at 10:18
Feb 26, 2018 at 6:47 history edited user1379857 CC BY-SA 3.0
added a paragraph answering the question better
Feb 26, 2018 at 1:58 history edited user1379857 CC BY-SA 3.0
fixed math typos
Feb 26, 2018 at 0:42 history answered user1379857 CC BY-SA 3.0