Timeline for Is drag coefficient in fluid dynamics a constant in every direction?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 23, 2018 at 12:26 | vote | accept | Userhanu | ||
| Feb 23, 2018 at 12:26 | history | edited | Bert Barrois | CC BY-SA 3.0 |
more damn typos
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| Feb 23, 2018 at 12:21 | comment | added | Bert Barrois | Yes, that will work provided that diffusion is isotropic. | |
| Feb 23, 2018 at 6:00 | comment | added | Userhanu | If I understand it right, you mean to say that if Diffusion is isotropic, i.e., \begin{bmatrix} D & 0 & 0 \\ 0 & D & 0 \\ 0 & 0 & D \end{bmatrix} Then I can write $$\frac{\textbf{F}}{\gamma}=\textbf{v}=(u \textbf{i}+v \textbf{j}+w \textbf{k}),$$ where $u,v,w$ are the velocities in three dimensions, derived by dividing a Force vector $\textbf{F}$ by constant drag coefficient $\gamma$. | |
| Feb 23, 2018 at 0:56 | history | answered | Bert Barrois | CC BY-SA 3.0 |