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Feb 22, 2018 at 11:02 vote accept Sergio
Feb 22, 2018 at 9:18 history edited Stijn CC BY-SA 3.0
Corrected statements about $p_x$ and $p_y$.
Feb 22, 2018 at 9:09 comment added Stijn You are completely right, thanks! I was too quick, made typos, and was thinking of the spin 1/2 representation, not the spin 1 case we are discussing here. I will edit my answer.
Feb 21, 2018 at 21:44 comment added Sergio If $p_z$ has $L_z = 0$, then $p_y$ --- $L_y = 0$ and $p_x$ --- $L_x = 0$. Am I right?
Feb 21, 2018 at 15:17 history answered Stijn CC BY-SA 3.0