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Thomas
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An adjoint fermion transforms in exactly the same way as an adjoint boson (like the gluon). We can write an adjoint fermion as a matrix valued field $$ \psi_{ab} = \psi^A (T^A)_{ab} $$ where $T^A=\frac{1}{2}\lambda^A$ are the $SU(N)$ generators. The Dirac operator acts as a covariant derivative in the adjoint representation $$ (D_\mu \psi)^A = (\partial_\mu \delta^{AB}+igf^{ACB}A^C_\mu)\psi^B $$
just like it acts on gluons.

An adjoint fermion transforms in exactly the same way as an adjoint boson (like the gluon). We can write an adjoint fermion as a matrix valued field $$ \psi_{ab} = \psi^A (T^A)_{ab} $$ where $T^A=\frac{1}{2}\lambda^A$ are the $SU(N)$ generators.

An adjoint fermion transforms in exactly the same way as an adjoint boson (like the gluon). We can write an adjoint fermion as a matrix valued field $$ \psi_{ab} = \psi^A (T^A)_{ab} $$ where $T^A=\frac{1}{2}\lambda^A$ are the $SU(N)$ generators. The Dirac operator acts as a covariant derivative in the adjoint representation $$ (D_\mu \psi)^A = (\partial_\mu \delta^{AB}+igf^{ACB}A^C_\mu)\psi^B $$
just like it acts on gluons.

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Thomas
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An adjoint fermion transforms in exactly the same way as an adjoint boson (like the gluon). We can write an adjoint fermion as a matrix valued field $$ \psi_{ab} = \psi^A (T^A)_{ij} $$$$ \psi_{ab} = \psi^A (T^A)_{ab} $$ where $T^A=\frac{1}{2}\lambda^A$ are the $SU(N)$ generators.

An adjoint fermion transforms in exactly the same way as an adjoint boson (like the gluon). We can write an adjoint fermion as a matrix valued field $$ \psi_{ab} = \psi^A (T^A)_{ij} $$ where $T^A=\frac{1}{2}\lambda^A$ are the $SU(N)$ generators.

An adjoint fermion transforms in exactly the same way as an adjoint boson (like the gluon). We can write an adjoint fermion as a matrix valued field $$ \psi_{ab} = \psi^A (T^A)_{ab} $$ where $T^A=\frac{1}{2}\lambda^A$ are the $SU(N)$ generators.

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Thomas
  • 18.9k
  • 1
  • 32
  • 61

An adjoint fermion transforms in exactly the same way as an adjoint boson (like the gluon). We can write an adjoint fermion as a matrix valued field $$ \psi_{ab} = \psi^A (T^A)_{ij} $$ where $T^A=\frac{1}{2}\lambda^A$ are the $SU(N)$ generators.