Timeline for Pressure versus mass and gravity
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Feb 15, 2018 at 22:45 | history | edited | BowlOfRed | CC BY-SA 3.0 |
added 863 characters in body
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| Feb 15, 2018 at 22:25 | comment | added | Richard L. McDonald | Great! Thank you. Now, there is zero gravitation at the very center but pressure remains from other layers above. Correct? What accounts for the pressure at the very center if gravity is zero? I think you answered the question in your response but I find that astounding! I had no idea that pressure would be present but zero gravity! | |
| Feb 15, 2018 at 22:15 | comment | added | BowlOfRed | Yes, that's correct. The layer immediately above you contributes no new pressure because $g=0$, but the sum of the pressure above remains. | |
| Feb 15, 2018 at 21:57 | comment | added | Richard L. McDonald | My question was intended to be specific to being located exactly at the center of a sphere the size of the Earth. Would gravitational acceleration be zero but pressure remain? | |
| Feb 15, 2018 at 21:39 | comment | added | Richard L. McDonald | Thank you for the response. I was only using the Earth as an example. How would the same question apply if we were, in theory, consider a large sphere, such as the Earth, but with a uniform consistency. Once we reach the center of that sphere, all of the mass is equally distributed in all directions. At that point, wouldn’t gravitational acceleration be neutralized for us but the pressure would still remain. Am I correct? | |
| Feb 15, 2018 at 21:22 | comment | added | Bert Barrois | This is good qualitative answer. To get numbers, you would have to integrate the equation of hydrostatic equilibrium downward from the surface. $dP/dz=\rho g$ | |
| Feb 15, 2018 at 18:56 | history | answered | BowlOfRed | CC BY-SA 3.0 |