Timeline for Question about the the velocity and acceleration in tensor notation
Current License: CC BY-SA 3.0
15 events
| when toggle format | what | by | license | comment | |
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| Nov 27 at 5:30 | answer | added | M. Hendy | timeline score: 1 | |
| Aug 4, 2020 at 23:29 | answer | added | HNaghieh | timeline score: 0 | |
| Jan 30, 2018 at 16:37 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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| Jan 30, 2018 at 16:31 | answer | added | Michele Grosso | timeline score: 1 | |
| Jan 26, 2018 at 20:10 | comment | added | Emil | This page is where I kind of understood what the connection was about en.m.wikipedia.org/wiki/Affine_connection | |
| Jan 26, 2018 at 19:32 | comment | added | Emil | Think this is the gist of it: $Z(t)$ gives points for times, $d_tZ(t)|_T$ gives direction of Z at time T, and $d_t d_t Z(t)$ is a function of the direction at two different points (the christoffel symbols maps the velocity vector basis in one tangent space to another). The basis for points is only isomorphic/same as basis for vectors in $\mathbb{R}^n$, or something like that. | |
| Jan 26, 2018 at 18:41 | comment | added | Rob | "Any help": en.wikipedia.org/wiki/Proper_acceleration#In_curved_spacetime (also scroll up). "More help": 🙅🏃 | |
| Jan 26, 2018 at 17:17 | comment | added | Slayer147 | But doesn't it make sense to me. From what you are saying when you act with the derivative, in one case you ignore the basis vectors, in the other you consider and hence differenciate them. | |
| Jan 26, 2018 at 17:08 | comment | added | knzhou | In general, position is not a vector; a position is a point. | |
| Jan 26, 2018 at 17:07 | comment | added | Slayer147 | I don't understand your reasoning, because position is a vector too, and velocity is the derivative of the position vector with respect to time. | |
| Jan 26, 2018 at 17:03 | comment | added | knzhou | It appears in the expression for the acceleration because velocity is a vector. | |
| Jan 26, 2018 at 17:02 | comment | added | Slayer147 | But how the Christoffel symbol appear then? | |
| Jan 26, 2018 at 17:02 | history | edited | Slayer147 | CC BY-SA 3.0 |
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| Jan 26, 2018 at 16:50 | comment | added | knzhou | It's because velocity and acceleration are vectors, but the position is not, it's a scalar. There is no need to differentiate basic vectors if you're just differentiating a scalar. | |
| Jan 26, 2018 at 16:43 | history | asked | Slayer147 | CC BY-SA 3.0 |