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Jan 13, 2018 at 7:40 history edited Voulkos CC BY-SA 3.0
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Jan 13, 2018 at 7:24 history edited Voulkos CC BY-SA 3.0
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Jan 13, 2018 at 2:00 history edited Voulkos CC BY-SA 3.0
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Jan 12, 2018 at 23:23 history edited Voulkos CC BY-SA 3.0
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Jan 12, 2018 at 23:10 comment added Voulkos @freecharly : I edit my answer leaving the incorrect equations of mine for comparison.
Jan 12, 2018 at 23:08 history edited Voulkos CC BY-SA 3.0
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Jan 12, 2018 at 19:41 comment added freecharly Your derivations are all perfect. Except for equation (10). As Anton Fetisov has pointed out, the path of the integration runs in the metallic wire where the electric field is zero, which is due to surface charges on the wire induced by the homogeneous field of the positive sheet charge. Therefore, as long as this time dependent path runs in the metallic wire circuit, the integral will be zero $$\oint\limits_{\partial S(t)}\left( \boldsymbol{\upsilon}\boldsymbol{\times} \mathbf{E}\right)\boldsymbol{\cdot} \mathrm d \boldsymbol{\ell}=0$$ Therefore also the RHS of equ.(11) is $=Edv$ !
Jan 12, 2018 at 15:43 history edited Voulkos CC BY-SA 3.0
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Jan 12, 2018 at 12:25 history edited Voulkos CC BY-SA 3.0
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Jan 12, 2018 at 8:40 history edited Voulkos CC BY-SA 3.0
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Jan 12, 2018 at 8:32 history undeleted user110781
Jan 12, 2018 at 8:32 history edited Voulkos CC BY-SA 3.0
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Jan 12, 2018 at 8:18 history edited Voulkos CC BY-SA 3.0
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Jan 12, 2018 at 8:10 history deleted user110781 via Vote
Jan 12, 2018 at 7:57 history answered Voulkos CC BY-SA 3.0