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tweaked formulations
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A.V.S.
A.V.S.
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This started as a comment but it got too big,

Note, that the temperature of the black-hole $$ T_{\mathrm {H} }=\frac {\hbar c^{3}}{8\pi GM} $$ (written in energetic units) with mass $1.9 \times 10^{10}\,\text{kg}$ would be about $0.56\, \text{GeV}$, which would mean that the Hawking radiation would include a lot of pions, muons, protons and corresponding antiparticles.

But this also implies that the equation for the radiated power (the one with $15360^{-1}$) is wrong. It is derived from Stefan–Boltzmann power law, which would be wrong for temperatures at which a lot of massive particles would be radiated. There would be additional channels for radiations of leptons, pions, with each contributing power comparable to EM radiation. So if we define 1 TW as total power of Hawking radiation in channels accessible'accessible' for the power generationengineering applications (EM radiation, leptons, mesons) and ignoring neutrinos and gravitons that are not readily usable, we would need to correspondingly increase the mass of black hole by some unknown factor. This would lower the temperature and increase horizon area. So from the 'engineering' standpoint the problem becomes somewhat simpler.

This started as a comment but it got too big,

Note, that the temperature of the black-hole $$ T_{\mathrm {H} }=\frac {\hbar c^{3}}{8\pi GM} $$ (written in energetic units) with mass $1.9 \times 10^{10}\,\text{kg}$ would be about $0.56\, \text{GeV}$, which would mean that the Hawking radiation would include a lot of pions, muons, protons and corresponding antiparticles.

But this also implies that the equation for the radiated power (the one with $15360^{-1}$) is wrong. It is derived from Stefan–Boltzmann power law, which would be wrong for temperatures at which a lot of massive particles would be radiated. There would be additional channels for radiations of leptons, pions, with each contributing power comparable to EM radiation. So if we define 1 TW as total power in channels accessible for the power generation (EM radiation, leptons, mesons) and ignoring neutrinos and gravitons that are not readily usable, we would need to correspondingly increase the mass of black hole by some unknown factor. This would lower the temperature and increase horizon area. So from the 'engineering' standpoint the problem becomes somewhat simpler.

This started as a comment but it got too big,

Note, that the temperature of the black-hole $$ T_{\mathrm {H} }=\frac {\hbar c^{3}}{8\pi GM} $$ (written in energetic units) with mass $1.9 \times 10^{10}\,\text{kg}$ would be about $0.56\, \text{GeV}$, which would mean that the Hawking radiation would include a lot of pions, muons, protons and corresponding antiparticles.

But this also implies that the equation for the radiated power (the one with $15360^{-1}$) is wrong. It is derived from Stefan–Boltzmann power law, which would be wrong for temperatures at which a lot of massive particles would be radiated. There would be additional channels for radiations of leptons, pions, with each contributing power comparable to EM radiation. So if we define 1 TW as total power of Hawking radiation in channels 'accessible' for the engineering applications (EM radiation, leptons, mesons) and ignoring neutrinos and gravitons that are not readily usable, we would need to correspondingly increase the mass of black hole by some unknown factor. This would lower the temperature and increase horizon area. So from the 'engineering' standpoint the problem becomes somewhat simpler.

Source Link
A.V.S.
A.V.S.
  • 16.6k
  • 2
  • 18
  • 46

This started as a comment but it got too big,

Note, that the temperature of the black-hole $$ T_{\mathrm {H} }=\frac {\hbar c^{3}}{8\pi GM} $$ (written in energetic units) with mass $1.9 \times 10^{10}\,\text{kg}$ would be about $0.56\, \text{GeV}$, which would mean that the Hawking radiation would include a lot of pions, muons, protons and corresponding antiparticles.

But this also implies that the equation for the radiated power (the one with $15360^{-1}$) is wrong. It is derived from Stefan–Boltzmann power law, which would be wrong for temperatures at which a lot of massive particles would be radiated. There would be additional channels for radiations of leptons, pions, with each contributing power comparable to EM radiation. So if we define 1 TW as total power in channels accessible for the power generation (EM radiation, leptons, mesons) and ignoring neutrinos and gravitons that are not readily usable, we would need to correspondingly increase the mass of black hole by some unknown factor. This would lower the temperature and increase horizon area. So from the 'engineering' standpoint the problem becomes somewhat simpler.