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Feb 4, 2018 at 2:30 vote accept Divyanshu
Jan 10, 2018 at 11:21 comment added Eric Duminil @Ian: Pedantically speaking, there's only a finite number of particles in the observable universe. So you won't find a $\mathrm{C-10^{81}}$ anytime soon.
Jan 10, 2018 at 10:23 comment added MSalters @Ian: I'm not that sure. When the halflife is lower than the time it takes light to travel from one side of the "nucleus" to the other, you don't have interaction between all neutrons involved.
Jan 10, 2018 at 1:26 answer added 0tyranny0poverty timeline score: 1
Jan 9, 2018 at 19:52 comment added Vendetta I've asked something related to this once in this site, and the full answer can be a bit complicated. In my question, the answer had this helpful link: www-nds.iaea.org/relnsd/vcharthtml/VChartHTML.html.
Jan 9, 2018 at 19:03 history tweeted twitter.com/StackPhysics/status/950805224033275904
Jan 9, 2018 at 18:59 comment added Jim Garrison Look up Nuclear Drip Line
Jan 9, 2018 at 17:39 comment added Ian Pedantically speaking, every element has an infinite number of isotopes. For example, there is a theoretical C-6, C-7, C-8, ... But we only refer to isotopes that we can isolate long enough to measure them. These need a "middle ground" of number of neutrons to be stable.
Jan 9, 2018 at 17:12 history edited Qmechanic CC BY-SA 3.0
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Jan 9, 2018 at 14:40 vote accept Divyanshu
Feb 4, 2018 at 2:30
Jan 9, 2018 at 14:36 answer added Slereah timeline score: 17
Jan 9, 2018 at 14:25 history asked Divyanshu CC BY-SA 3.0