Timeline for Why does centrifugal force contribute to potential energy?
Current License: CC BY-SA 3.0
18 events
| when toggle format | what | by | license | comment | |
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| Dec 29, 2017 at 12:10 | answer | added | sammy gerbil | timeline score: 1 | |
| Dec 28, 2017 at 17:38 | comment | added | DJohnM | Potential energy, relative to what zero level? | |
| Dec 28, 2017 at 13:47 | vote | accept | segevp | ||
| Dec 28, 2017 at 13:24 | comment | added | Qmechanic♦ | Every time you have a conserved field, you may introduce a potential for it. | |
| Dec 28, 2017 at 13:14 | comment | added | Shing | @Mitchell I wrote an answer to this question, feel free to suggest anything. (my comment was written in a hurry, hence not quite precise) | |
| Dec 28, 2017 at 13:12 | answer | added | Shing | timeline score: 2 | |
| S Dec 28, 2017 at 10:04 | history | suggested | QuIcKmAtHs | CC BY-SA 3.0 |
grammar and clarity
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| Dec 28, 2017 at 9:18 | comment | added | Mitchell | Magnitude of $\omega$ determines the magnitude of centrifugal force (at constant r). | |
| Dec 28, 2017 at 9:11 | review | Suggested edits | |||
| S Dec 28, 2017 at 10:04 | |||||
| Dec 28, 2017 at 9:09 | comment | added | Mitchell | @Shing, You don't have to keep applying energy to keep the system rotating. The normal force applied by the body to the tube does not produce any torque about the axis of rotation (Newton's first law applies here). I believe this is not the answer to the question. For equilibrium, the centrifugal force will be cancelled out by the horizontal component of normal force and the weight of the body by the vertical one. So, the height to which the body rises depends on $\omega$ or centrifugal force. | |
| Dec 28, 2017 at 8:58 | comment | added | segevp | @Steeven this is not the answer but what seems to be right in my wrong prespective | |
| Dec 28, 2017 at 8:56 | comment | added | Steeven | What do you mean by the centrifugal force also having a contribution? Where do you see such a contribution in the result? | |
| Dec 28, 2017 at 8:22 | comment | added | Shing | It is the one who rotates the whole thing (he has to keep inputing energy, s.t. the whole thing rotate at a fixed rate) contributing potential energy. | |
| Dec 28, 2017 at 8:20 | comment | added | Mitchell | I strongly suggest you to add your ideas to your post, otherwise your post will be put on hold as a homework question. | |
| S Dec 28, 2017 at 8:17 | history | suggested | QuIcKmAtHs | CC BY-SA 3.0 |
grammar and clarity
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| Dec 28, 2017 at 8:14 | review | Suggested edits | |||
| S Dec 28, 2017 at 8:17 | |||||
| Dec 28, 2017 at 8:13 | history | edited | Qmechanic♦ |
edited tags
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| Dec 28, 2017 at 8:12 | history | asked | segevp | CC BY-SA 3.0 |