Timeline for What do imaginary numbers practically represent in the Schrödinger equation?
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Dec 20, 2017 at 4:25 | comment | added | Bob Bee | Yes, you can, you are right. The 1 is also done with sine squared plus cos squared, so not clear it's a deal breaker. But the thing is that i's also give you a vector space, more naturally than other ways with sines and cosines -- you have to have a way to have sines and cosines be orthogonal, in signal processing its I and Q. You somehow need the vector space, with R or C. | |
Dec 20, 2017 at 1:47 | comment | added | Jay | You can also have phase with real numbers. I think it's important in QM that unlike $\sin \omega t$, the magnitude of $e^{i \omega t}$ is 1 for all $t$. | |
Dec 20, 2017 at 1:02 | history | answered | Bob Bee | CC BY-SA 3.0 |