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Dec 22, 2023 at 7:07 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
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Apr 15, 2023 at 1:22 comment added FlatterMann I think this is a bit of a magnetic equivalent of the self-energy of a point charge. Nature simply doesn't allow us to reduce the size of charge/current distributions to zero without including, at least, a logarithmic divergence. Maybe the problem is a little deeper, though, than the usual static analysis suggests. In a relativistic universe no such thing as a "static" field can exist. The formation transient always takes infinite time to spread to all of space. At the "small end", the formation of an infinitesimal charge/current density would cause an infinite spike of em radiation.
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Jul 15, 2021 at 17:27 comment added Leviathan @RelativisticDolphin Your last sentence. Do you mean thickness of the loop, or area within the loop? You should provide a formula.
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Jul 1, 2019 at 23:01 comment added Philip Wood An approximate formula for the flux linked with a circular current-carrying loop of radius $𝑟$ made from wire of radius 𝑎 is $$\Phi=\mu_0 I𝑟 \ln(1.39𝑟/𝑎).$$ Is this what you arrived at (maybe without the 1.39) by considering the 'returning' flux outside the loop?
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Dec 15, 2017 at 12:52 answer added hyportnex timeline score: 1
Dec 14, 2017 at 8:11 comment added RelativisticDolphin @PhilipWood yes I did and I got an expression independent of the thickness. I used the scalar magnetic potential and the magnetic moment of the wire loop.
Dec 13, 2017 at 22:48 comment added Philip Wood You are right up to your last paragraph. But regarding this last paragraph, have you actually tried to calculate the inductance of a loop by integrating up the 'external' flux, as you propose? I can't do so (which may not be saying very much).
Dec 13, 2017 at 22:02 history edited RelativisticDolphin CC BY-SA 3.0
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Dec 13, 2017 at 21:51 history asked RelativisticDolphin CC BY-SA 3.0