Timeline for How high should be the edge of a billiard table to not allow undesirable pressures on balls when bouncing off?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 27, 2017 at 22:45 | vote | accept | SlowerPhoton | ||
| Nov 23, 2017 at 12:00 | comment | added | Floris | Use $m\Delta v = F \Delta t$ instead - you don't need to know the acceleration, only the integral of acceleration with time (change in velocity). | |
| Nov 23, 2017 at 9:06 | comment | added | SlowerPhoton | EDIT: It just ocurred to me: isn't $a = \Delta v$? | |
| Nov 23, 2017 at 8:57 | comment | added | SlowerPhoton | Thank you. I am sorry if this is stupid, but the last time I've taken any lessons on physics was on high school (I had to read a lot of articles on wiki just to understand a bit of your comment). And it is not a graded homework, more like an exercise on integration :) So if $L = I\omega$: $\Delta L = Fh\Delta t $. $\Delta L = \frac25 m \Delta v r$ and $F = ma$. I can see I can get rid off $m$, but what is $a$, the ball is certainly not accelerating? | |
| Nov 22, 2017 at 22:52 | history | answered | Floris | CC BY-SA 3.0 |