Timeline for In Inelastic collision, momentum is conserved while Kinetic Energy is not, Why?
Current License: CC BY-SA 3.0
8 events
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Nov 15, 2017 at 1:27 | comment | added | docscience | Heat in the form of radiation, maybe loss in sound waves. The energy is conserved | |
Nov 14, 2017 at 21:34 | comment | added | TontyTon | In your example, I understood the conservation of momentum, but there is no effect of release of heat energy (or other type of energy), since the body is finally coming to a rest. | |
Nov 14, 2017 at 21:23 | comment | added | docscience | Please think more about my example and how you start with zero momentum, then wind up with zero momentum, masses being equal. $mv + (-mv) = 0$ v is a vector, therefor momentum is a vector. | |
Nov 14, 2017 at 21:16 | comment | added | TontyTon | Sir, I am not contradicting momentum conservation theory, I accept it. But I am unable to understand how it is taking hold here? How even after reduce in speed of bodies momentum is conserved? | |
Nov 14, 2017 at 21:12 | comment | added | docscience | In the real world you will indeed see a final velocity from the original experiment since you cannot make everything perfect. But still in the real world momentum is conserved, just as in the world of thought experiments! | |
Nov 14, 2017 at 21:10 | comment | added | docscience | That's a different thought experiment. And in that experiment if you have a small velocity afterwards you have to conclude that (1) the balls were not exactly the same mass or (2) their speeds were not exactly the same or (3) their velocities were not exactly colinear or (4) any combination of the prior three possibilities. | |
Nov 14, 2017 at 21:06 | comment | added | TontyTon | Yes, but when there is some final velocity of both the objects? and the 2 objects don't have initially equal velocity (when the objects have equal velocity, then only the objects in your answer will come to rest)? | |
Nov 14, 2017 at 21:03 | history | answered | docscience | CC BY-SA 3.0 |