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Jul 6, 2021 at 15:05 comment added zyy I found a related discussion here.
Jul 6, 2021 at 14:59 comment added zyy Can $\mu _R$ and $\mu _F$ be the same if they are regulating different types of singularities?
Nov 2, 2017 at 17:04 comment added user154997 Well, best is that I should show some Feynman diagrams to clarify! I'll update my answer later… There is also the issue of jets, which I ignored, but your question was general enough that this would fit actually.
Nov 2, 2017 at 17:02 comment added user154997 There are two partons in the initial state because we are looking at $pp$ collisions, one parton from each protons. There is only one parton in the final state because I looked only at the inclusive production of one single hadron. Read again the definition I gave of f and F and it should make sense. I could have looked at the production of two hadrons: then I would have got 2 final partons and two F's, one for each of them. Note the X in the partonic cross-section: it hides other quarks, as many a necessary for the given order of $\alpha_S$.
Nov 2, 2017 at 16:09 comment added MycrofD @LucJ.Bourhis doubt. why do we have three partons i,j,k? is it about colour neutrality or something else about the decay process example given? and why i,j are for f(x) but k is for F(z)?
Oct 27, 2017 at 21:48 history edited user154997 CC BY-SA 3.0
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Oct 27, 2017 at 14:30 comment added user154997 Yes, indeed, sorry. I also fixed the notation for the partonic cross-section in the second formula.
Oct 27, 2017 at 14:29 history edited user154997 CC BY-SA 3.0
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Oct 27, 2017 at 14:08 comment added MycrofD what are dx_1, dx_x in the first and second integrands respectively? or is that just a typo? are you missing dx in the third integrand?
Oct 26, 2017 at 13:32 history edited user154997 CC BY-SA 3.0
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Oct 26, 2017 at 13:20 history edited user154997 CC BY-SA 3.0
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Oct 26, 2017 at 11:09 vote accept MycrofD
Oct 26, 2017 at 9:17 history answered user154997 CC BY-SA 3.0