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John Alexiou
John Alexiou
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You are comparing the velocities of the centers of mass, instead of the velocities of the points of contact.

The true elastic contact relationship is expressed for the contact point A.

$$ (v_{df} - v_{sf}^A) = -\epsilon (v_{di} - v_{si}^A) $$ where $v_{si}^A = 0 $, and $v_{sf}^A = v_{sf} + c\,\omega_f $, with $c$ the distance of the center of mass of the stick to the contact point, and $\epsilon=1$ the COR.

You are comparing the velocities of the centers of mass, instead of the velocities of the points of contact.

The true elastic contact relationship is

$$ (v_{df} - v_{sf}^A) = -\epsilon (v_{di} - v_{si}^A) $$ where $v_{si}^A = 0 $, and $v_{sf}^A = v_{sf} + c\,\omega_f $, with $c$ the distance of the center of mass of the stick to the contact point, and $\epsilon=1$ the COR.

You are comparing the velocities of the centers of mass, instead of the velocities of the points of contact.

The true elastic contact relationship is expressed for the contact point A.

$$ (v_{df} - v_{sf}^A) = -\epsilon (v_{di} - v_{si}^A) $$ where $v_{si}^A = 0 $, and $v_{sf}^A = v_{sf} + c\,\omega_f $, with $c$ the distance of the center of mass of the stick to the contact point, and $\epsilon=1$ the COR.

Source Link
John Alexiou
John Alexiou
  • 39.3k
  • 6
  • 72
  • 182

You are comparing the velocities of the centers of mass, instead of the velocities of the points of contact.

The true elastic contact relationship is

$$ (v_{df} - v_{sf}^A) = -\epsilon (v_{di} - v_{si}^A) $$ where $v_{si}^A = 0 $, and $v_{sf}^A = v_{sf} + c\,\omega_f $, with $c$ the distance of the center of mass of the stick to the contact point, and $\epsilon=1$ the COR.