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David Z
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Unitary operator as Why is the $\varepsilon^2$ term in an infinitesimal transformation equal to zero?

Somebody can give me a hand with this?

Given the unitary operator $U=1+i\varepsilon F$ (where $\varepsilon$ is an infinitesimal escalarscalar), in order to prove that $F$ is HermiteanHermitian:

$$UU^{+}=1$$

$$(1+i\varepsilon F) (1-i\varepsilon F^+)=1$$

$$1+i\varepsilon F-i\varepsilon F^+ +\varepsilon^2 FF^+=1$$$$\begin{align} UU^{\dagger} &= 1 \\ (1+i\varepsilon F) (1-i\varepsilon F^\dagger) &= 1 \\ 1+i\varepsilon F-i\varepsilon F^\dagger +\varepsilon^2 FF^\dagger &= 1 \end{align}$$

It seems that $F$ must be equal to $F^+$$F^\dagger$ to satisfy that expression, but how can the remaining term be equal to zero? $(\varepsilon^2 FF^+\overset{\large\text{?}} = 0)$$(\varepsilon^2 FF^\dagger\overset{\large\text{?}} = 0)$

Unitary operator as an infinitesimal transformation

Somebody can give me a hand with this?

Given the unitary operator $U=1+i\varepsilon F$ (where $\varepsilon$ is an infinitesimal escalar), in order to prove that $F$ is Hermitean:

$$UU^{+}=1$$

$$(1+i\varepsilon F) (1-i\varepsilon F^+)=1$$

$$1+i\varepsilon F-i\varepsilon F^+ +\varepsilon^2 FF^+=1$$

It seems that $F$ must be equal to $F^+$ to satisfy that expression, but how can the remaining term be equal to zero? $(\varepsilon^2 FF^+\overset{\large\text{?}} = 0)$

Why is the $\varepsilon^2$ term in an infinitesimal transformation equal to zero?

Given the unitary operator $U=1+i\varepsilon F$ (where $\varepsilon$ is an infinitesimal scalar), in order to prove that $F$ is Hermitian:

$$\begin{align} UU^{\dagger} &= 1 \\ (1+i\varepsilon F) (1-i\varepsilon F^\dagger) &= 1 \\ 1+i\varepsilon F-i\varepsilon F^\dagger +\varepsilon^2 FF^\dagger &= 1 \end{align}$$

It seems that $F$ must be equal to $F^\dagger$ to satisfy that expression, but how can the remaining term be equal to zero? $(\varepsilon^2 FF^\dagger\overset{\large\text{?}} = 0)$

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Qmechanic
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Unitary operator as an infinitesimal transformation

Somebody can give me a hand with this?

Given the unitary operator $U=1+i\varepsilon F$ (where $\varepsilon$ is an infinitesimal escalar), in order to prove that $F$ is Hermitean:

$$UU^{+}=1$$

$$(1+i\varepsilon F) (1-i\varepsilon F^+)=1$$

$$1+i\varepsilon F-i\varepsilon F^+ +\varepsilon^2 FF^+=1$$

It seems that $F$ must be equal to $F^+$ to satisfy that expression, but how can the remaining term be equal to zero? $(\varepsilon^2 FF^+\overset{\large\text{?}} = 0)$