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Oct 10, 2017 at 16:45 comment added Imtiaz Raqib I realized that last night and fixed it. Thank you so much for your help! :D
Oct 10, 2017 at 16:44 vote accept Imtiaz Raqib
Oct 10, 2017 at 13:04 comment added FGSUZ Nice fail. Well, the theorem above is right and the reasoning is primarily true. The thing is that the normal force is not that one. If you're pulling with a force at angle $\theta$, the force giving work to the $E_k$ is $F\cdot \cos \theta$ but the rest is $F\cdot\sin \theta$. This force acts in the vertical direction and it partially compensates the weight, so the normal force is not $mg$ but $mg-F\cdot \sin \theta$.
Oct 10, 2017 at 3:32 comment added Imtiaz Raqib When I check my answer, it says I am wrong. To put it better; F = 611 ; m = 69.9 ; θ = 36.3 ; μ = 0.139 ; d = 5.62 Plugging all that gives me 2230 J (Keeping sig digs in mind) and my portal says it is wrong.
Oct 6, 2017 at 20:48 vote accept Imtiaz Raqib
Oct 10, 2017 at 3:49
Oct 6, 2017 at 18:23 review Low quality answers
Oct 6, 2017 at 18:42
Oct 6, 2017 at 18:06 history answered FGSUZ CC BY-SA 3.0