I have had this doubt since forever.
1)TheThe question first of all asks work for done BY gasby or work done ONon the gas which already means two different things. Isn't this like askingHow does that make sense? If I do work one$mgh$ on a block by hand in raising is mgh. Whereasit, the work done by gravitythe block on me is -mgh? Two of them$-mgh$. They have the same magnitude and opposite sign so.
In physics we use the sign convention of ∆W=P∆V for work done BY gas. So if it should be both +expansion it is Positive and vice versa. However in chemistry we use ∆W=-P∆V for work done by gas and expansion is negative. I understand that overall the sign convention give same answer for ∆U and ∆Q as one has Q=U+W whereas other one is U=Q+W. But doesn't this mean work done according to your sign convention will change?
- In physics we use the sign convention of ∆W=P∆V for work done BY gas. So if it expansion it is Positive and vice versa. However in chemistry we use ∆W=-P∆V for work done by gas and expansion is negative. I understand that overall the sign convention give same answer for ∆U and ∆Q as one has Q=U+W whereas other one is U=Q+W. But dissent this mean work done according to your sign convention will change?
CorrectThe correct answer is given assupposed to be D).