Timeline for Steps of measurement to verify the Heisenberg uncertainty principle
Current License: CC BY-SA 3.0
8 events
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| Aug 24, 2017 at 14:20 | comment | added | ZeroTheHero | @SRA I've added a link to a paper that deals with some of the issues of your post. | |
| Aug 24, 2017 at 14:00 | history | edited | ZeroTheHero | CC BY-SA 3.0 |
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| Aug 24, 2017 at 13:44 | comment | added | SRS | I have added an addendum which really creates a confusion with this way of measuremnet. | |
| Aug 24, 2017 at 13:43 | history | edited | ZeroTheHero | CC BY-SA 3.0 |
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| Aug 24, 2017 at 13:41 | history | edited | ZeroTheHero | CC BY-SA 3.0 |
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| Aug 24, 2017 at 13:07 | comment | added | ZeroTheHero | Basically yes since the operator $A$ acting on your state $\Psi$ results in a different wave function. Clearly average values for instance need not be the same for $\psi_A=A\Psi$ and $\psi_B=B\Psi$. | |
| Aug 24, 2017 at 12:32 | comment | added | SRS | Do you mean the probability distribution changes and there is no meaning in comparing variances calculated from different probability distributions?@ZeroTheHero | |
| Aug 24, 2017 at 12:29 | history | answered | ZeroTheHero | CC BY-SA 3.0 |