Timeline for Pouring coffee in a rotating space station
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Aug 20, 2017 at 19:19 | vote | accept | David | ||
| Aug 18, 2017 at 19:29 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
deleted 117 characters in body; edited tags
|
| Aug 18, 2017 at 14:45 | answer | added | David | timeline score: 0 | |
| Aug 17, 2017 at 21:48 | review | Close votes | |||
| Aug 18, 2017 at 7:40 | |||||
| Aug 17, 2017 at 21:28 | comment | added | dmckee --- ex-moderator kitten | The $\vec{v}$ there is the one that a person standing in the habitat measures. If you're talking about pouring coffee it is the velocity of the coffee according to you. So it is approximately 'down' (i.e. radially outward from your current location) and has a magnitude that starts near zero as the coffee flows over the lip of the spout and increases as it falls. | |
| Aug 17, 2017 at 21:25 | comment | added | David | See, here's where I start to get lost, and start needing Physics SE. :) I've been relying on online calculators to get this far. Is that $\vec{v}$ equivalent to the tangential velocity here? I don't know what other velocity we'd be talking about, but tangential velocity isn't perpendicular to angular velocity... is it? And I'm afraid I don't know how to figure a cross product. I would fail your mechanics class quite completely, I'm afraid. | |
| Aug 17, 2017 at 20:51 | comment | added | dmckee --- ex-moderator kitten | $\vec{v}$ is the velocity of the affected object in the rotating frame. And you get the direction from the cross-product $\vec{a}_\text{cor} = -2 \vec{\omega} \times \vec{v}$ notice that the version you wrote assumes that the angular velocity and object velocity are perpendicular—but they are in the pouring problem. | |
| Aug 17, 2017 at 20:47 | comment | added | David | @dmckee High school physics was a long time ago. :) Angular velocity I have, but I'm not sure what to make of the velocity vector there. Where does that come from? And which direction is the acceleration? Antispinward, I guess. | |
| Aug 17, 2017 at 20:43 | comment | added | dmckee --- ex-moderator kitten | This is a problem I give my mechanics students on a regular basis, and you've written down what you need to know to at least get a first approximation. What's stopping from simply plugging in a couple of values and computing? | |
| Aug 17, 2017 at 14:26 | history | asked | David | CC BY-SA 3.0 |