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Aug 7, 2017 at 0:53 history edited Eddy CC BY-SA 3.0
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Aug 7, 2017 at 0:48 history edited Eddy CC BY-SA 3.0
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Aug 6, 2017 at 23:43 comment added Eddy I believe so. It's probably worth pointing out also that the surface tension above is not going to be the surface tension of whatever fluid your using to make bubbles. To use that you would have to consider the three part problem of outside, bubble, inside, and include the pressure of the bubble fluid, and interior and exterior radii of the spheres, along with two surface tension equations and enforce a particular volume of bubble fluid. :)
Aug 6, 2017 at 23:35 comment added TSL Thank you Eddy! Very nicely explained. Following through on your logic, I can now calculate dPi/dPo, and if I've chicken-scratched my calculations out correctly, it turns out to be 3k / [ 2k + (Po/Pi) k]. So, as long as the bubble started out higher pressure inside than outside; dPi/dPo is greater than one, and the pressure inside the bubble always increases faster than any increase to the external pressure; so that the gauge pressure always increases, and the bubble always shrinks. Makes sense now. Thank you!
Aug 6, 2017 at 20:18 history edited Eddy CC BY-SA 3.0
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Aug 6, 2017 at 20:10 history edited Eddy CC BY-SA 3.0
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Aug 6, 2017 at 20:04 history answered Eddy CC BY-SA 3.0