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Mark H
Mark H
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If there is a block that is placed at the rim of a turntable. And, and we start rotating this turntable.., I know that while the turntable is rotating  , a centripetal force is acting on the block  . This force is the static friction. If we increase the angular speed of the turntable  , the static frictinfriction must increase (according to newton's 2nd law inwith the normal direction F=mv^2/r,where v is the speed of the block,r is the radius , m is the mass of the block). If we continue increasing the angular speed of the turntable, kinetic friction will act as a centripetal force instead of the static friction.. And the block will slip.. my question is, In what direction will the block slip? Will the block slip in the tangential direction? Or will it slip at an angle from the tangential direction??
My expectations(I don't know if this is true) " according to newton's 2nd law F=mv^2/r Since v$F=mv^2/r$, where $v$ is the speed of the block, $r$ is the radius, and $m$ is the mass of the block). If we continue increasing the angular speed of the turntable, kinetic friction will act as a centripetal force instead of the static friction and the block will slip. My question is, in what direction will the block slip? Will the block slip in the tangential direction? Or will it slip at an angle from the tangential direction?

My expectations(I don't know if this is true) is that according to newton's 2nd law $F=mv^2/r$, since $v$ is very large and F$F$ (kinetic friction force) is very small,, then rthen $r$ must become very large. When the radius of any circle (in general) isis very large, thethe circle becomes like a straight line (I mean that the staighta straight line is a circle such that the radius goes to infinity, soso as r$r$ gets larger, the block will kinda move in a straight line). Which means, which means that the block will slip in the tangential direction ".

If there is a block that is placed at the rim of a turntable. And we start rotating this turntable.. I know that while the turntable is rotating  , a centripetal force is acting on the block  . This force is the static friction. If we increase the angular speed of the turntable  , the static frictin must increase (according to newton's 2nd law in the normal direction F=mv^2/r,where v is the speed of the block,r is the radius , m is the mass of the block). If we continue increasing the angular speed of the turntable, kinetic friction will act as a centripetal force instead of the static friction.. And the block will slip.. my question is, In what direction will the block slip? Will the block slip in the tangential direction? Or will it slip at an angle from the tangential direction??
My expectations(I don't know if this is true) " according to newton's 2nd law F=mv^2/r Since v is very large and F (kinetic friction force) is very small,, then r must become very large. When the radius of any circle (in general) is very large, the circle becomes like a straight line (I mean that the staight line is a circle such that the radius goes to infinity, so as r gets larger, the block will kinda move in a straight line). Which means, the block will slip in the tangential direction "

If there is a block that is placed at the rim of a turntable, and we start rotating this turntable, I know that while the turntable is rotating, a centripetal force is acting on the block. This force is static friction. If we increase the angular speed of the turntable, the static friction must increase (according to newton's 2nd law with the normal direction $F=mv^2/r$, where $v$ is the speed of the block, $r$ is the radius, and $m$ is the mass of the block). If we continue increasing the angular speed of the turntable, kinetic friction will act as a centripetal force instead of the static friction and the block will slip. My question is, in what direction will the block slip? Will the block slip in the tangential direction? Or will it slip at an angle from the tangential direction?

My expectations(I don't know if this is true) is that according to newton's 2nd law $F=mv^2/r$, since $v$ is very large and $F$ (kinetic friction force) is very small, then $r$ must become very large. When the radius of any circle (in general) is very large, the circle becomes like a straight line (I mean that a straight line is a circle such that the radius goes to infinity, so as $r$ gets larger, the block will kinda move in a straight line), which means that the block will slip in the tangential direction.

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Eman.suradi
Eman.suradi
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If there is a block that is placed at the rim of a turntable. And we start rotating this turntable.. I know that while the turntable is rotating , a centripetal force is acting on the block . This force is the static friction. If we increase the angular speed of the turntable , the static frictin must increase (according to newton's 2nd law in the normal direction F=mv^2/r,where v is the speed of the block,r is the radius , m is the mass of the block). If we continue increasing the angular speed of the turntable, kinetic friction will act as a centripetal force instead of the static friction.. And the block will slip.. my question is, In what direction will the block slip? Will the block slip in the tangential direction? Or will it slip at an angle from the tangential direction??
My expectations(I don't know if this is true) " according to newton's 2nd law F=mv^2/r Since v is very large and F is (kinetic friction force) is very small,, then r must become very large,, when. When the radius of any circle (in general) is very large, the circle becomes like a straight line (I mean that the staight line is a circle such that the radius goes to infinity, so as r gets larger, the block will kinda move in a straight line). Which means, the block will slip in the tangential direction "

If there is a block that is placed at the rim of a turntable. And we start rotating this turntable.. I know that while the turntable is rotating , a centripetal force is acting on the block . This force is the static friction. If we increase the angular speed of the turntable , the static frictin must increase (according to newton's 2nd law in the normal direction F=mv^2/r,where v is the speed of the block,r is the radius , m is the mass of the block). If we continue increasing the angular speed of the turntable, kinetic friction will act as a centripetal force instead of the static friction.. And the block will slip.. my question is, In what direction will the block slip? Will the block slip in the tangential direction? Or will it slip at an angle from the tangential direction??
My expectations(I don't know if this is true) " according to newton's 2nd law F=mv^2/r Since v is very large and F is very small,, then r must become very large,, when the radius of any circle (in general) is very large, the circle becomes like a straight line (I mean that the staight line is a circle such that the radius goes to infinity, so as r gets larger, the block will kinda move in a straight line). Which means, the block will slip in the tangential direction "

If there is a block that is placed at the rim of a turntable. And we start rotating this turntable.. I know that while the turntable is rotating , a centripetal force is acting on the block . This force is the static friction. If we increase the angular speed of the turntable , the static frictin must increase (according to newton's 2nd law in the normal direction F=mv^2/r,where v is the speed of the block,r is the radius , m is the mass of the block). If we continue increasing the angular speed of the turntable, kinetic friction will act as a centripetal force instead of the static friction.. And the block will slip.. my question is, In what direction will the block slip? Will the block slip in the tangential direction? Or will it slip at an angle from the tangential direction??
My expectations(I don't know if this is true) " according to newton's 2nd law F=mv^2/r Since v is very large and F (kinetic friction force) is very small,, then r must become very large. When the radius of any circle (in general) is very large, the circle becomes like a straight line (I mean that the staight line is a circle such that the radius goes to infinity, so as r gets larger, the block will kinda move in a straight line). Which means, the block will slip in the tangential direction "

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Eman.suradi
Eman.suradi
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How will "a block on a turntable" move when the turntable move very fast?

If there is a block that is placed at the rim of a turntable. And we start rotating this turntable.. I know that while the turntable is rotating , a centripetal force is acting on the block . This force is the static friction. If we increase the angular speed of the turntable , the static frictin must increase (according to newton's 2nd law in the normal direction F=mv^2/r,where v is the speed of the block,r is the radius , m is the mass of the block). If we continue increasing the angular speed of the turntable, kinetic friction will act as a centripetal force instead of the static friction.. And the block will slip.. my question is, In what direction will the block slip? Will the block slip in the tangential direction? Or will it slip at an angle from the tangential direction??
My expectations(I don't know if this is true) " according to newton's 2nd law F=mv^2/r Since v is very large and F is very small,, then r must become very large,, when the radius of any circle (in general) is very large, the circle becomes like a straight line (I mean that the staight line is a circle such that the radius goes to infinity, so as r gets larger, the block will kinda move in a straight line). Which means, the block will slip in the tangential direction "