Timeline for Proving that the Electromagnetic Field Tensor is a Tensor and its significance?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 25, 2017 at 23:26 | vote | accept | aidangallagher4 | ||
| Jun 25, 2017 at 23:19 | answer | added | user4552 | timeline score: 2 | |
| Jun 25, 2017 at 19:22 | comment | added | user154420 | en.m.wikipedia.org/wiki/Electromagnetic_tensor | |
| Jun 25, 2017 at 19:14 | comment | added | user154420 | Something that you might consider. $F_{\mu\nu}$ has significance also in relation to the potentials involved in creating it (by diffing the potentials, as in your question you ask what the derivatives represent. What do you get when you diff a potential? ) . So although different observers will measure different E and B fields, what is it that remains invariant to all observers? | |
| Jun 25, 2017 at 19:14 | answer | added | gented | timeline score: 0 | |
| Jun 25, 2017 at 18:55 | history | edited | aidangallagher4 | CC BY-SA 3.0 |
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| Jun 25, 2017 at 18:38 | comment | added | Avantgarde | Okay, yes. This is Lorentz covariance. Also, in the equation you wrote, it should be $F_{\mu \nu}$ and not $F^{\mu \nu}$. Both sides of the equation must transform in the same manner. | |
| Jun 25, 2017 at 18:27 | comment | added | aidangallagher4 | @Avantgarde I mean that since it is a tensor it is independent of the choice of coordinates used, so someone moving close to the speed of light or in a strong gravitational field would use the same equation as someone standing still relative to the system being measured or not in a gravitational field | |
| Jun 25, 2017 at 18:24 | comment | added | Avantgarde | What do you mean by 'significance that it is a tensor that it becomes true in all reference frames' ? | |
| Jun 25, 2017 at 15:50 | history | asked | aidangallagher4 | CC BY-SA 3.0 |