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Feb 15 at 13:19 comment added ProfRob There is no "the escape velocty". In GR, the escape velocity depends on the direction of launch.
Aug 11, 2012 at 22:20 comment added Anixx It can if it comes from a place just above the horizon. But it looses much of its energy and becomes redshifted.
Aug 11, 2012 at 14:18 comment added seriousdev But if the escape velocity is $c$, why can't light escape?
Aug 10, 2012 at 21:44 history edited Keith Thompson CC BY-SA 3.0
Mention event horizon
Aug 10, 2012 at 21:38 comment added Anixx Yes, that means event horizon.
Aug 10, 2012 at 21:38 comment added Keith Thompson Where the "surface" is the event horizon. There isn't necessarily any material surface there.
Aug 10, 2012 at 21:34 history answered Anixx CC BY-SA 3.0