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Aug 8, 2012 at 4:16 comment added Yrogirg see meta.math.stackexchange.com/questions/1773/… and en.wikipedia.org/wiki/…
Aug 7, 2012 at 20:29 comment added Shaktyai Thanks for the typing, you are the second one today to edit my post. I may need to take a few minutes to learn tex, math ML or whatever. Otherwise I am going to be kicked out ...
S Aug 7, 2012 at 18:15 history suggested Yrogirg CC BY-SA 3.0
expansion added
Aug 7, 2012 at 17:20 comment added Yrogirg I meant you put it in your answer, since it is not only me who will want to see it. I've made the edit.
Aug 7, 2012 at 17:19 review Suggested edits
S Aug 7, 2012 at 18:15
Aug 7, 2012 at 14:27 comment added Shaktyai h=(3×r^2*P/ρg+r^3)^(1/3)−r h=r*(3*P/ρgr +1)^(1/3)-r (1+x)^t=1+t*x+o(x^2) take x=3*P/ρgr And you get h=P/ρg
Aug 7, 2012 at 14:07 comment added Yrogirg +1, though I had to think a bit what formulas are you talking about (for $h$ it turned out). But it would be nice if you could provide 1-2 terms of the expansion.
Aug 7, 2012 at 13:58 history answered Shaktyai CC BY-SA 3.0