Timeline for Magnetic levitated electric wire
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 21, 2017 at 22:35 | comment | added | Andrew Murphy | Both AC and DC should work if you are using a separate coil to generate the opposing field. Probably the biggest real world challenge is finding a power supply to run everything, and making sure your wires can take the current for each one. | |
| May 20, 2017 at 22:14 | comment | added | Alireza | What if I use DC current in both the wire and the coils? | |
| May 20, 2017 at 22:12 | comment | added | Alireza | Thank you for your reply. I thought about this demo for a while and I think the right way to show this the way I want is to use Helmholtz coils to generate a magnetic field and pass a current carrying wire between them. I used the equation for Helmholtz coil and the one I mentioned above (IB=Ag) and I got this: (Sorry about typing formulas like this) I(wire)*I(coil)*N(coil)/(R(coil)*A) = 1.09*10^7 So if I have a coil of N=1000 and R=7 cm and a wire of A=50 g/m I can use ~6 A current for the wire and coil both. I know the theory, But what would cause trouble when I do it in real world? | |
| May 18, 2017 at 20:29 | comment | added | HolgerFiedler | My comment was to short jumped. Nice answer. | |
| May 18, 2017 at 11:26 | history | answered | Andrew Murphy | CC BY-SA 3.0 |