Timeline for Does the expression of the orbital magnetic dipole moment have $c$?
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Aug 6, 2012 at 19:08 | vote | accept | Revo | ||
| Jul 30, 2012 at 0:47 | comment | added | Siyuan Ren | @Revo: All formulas in this article are correct in SI units, but in other unit systems, the formulas may need to be changed. For example, in SI units, a loop of current with current I and area A has magnetic moment I×A (see below), but in Gaussian units the magnetic moment is I×A/c.(en.wikipedia.org/wiki/Magnetic_moment#Units) | |
| Jul 29, 2012 at 23:05 | comment | added | Revo | Bohr magneton has different expressions in different unit systems, one with c and one without, but not the magnetic dipole moment. The magnetic dipole moment by definition equals the current times the area enclosed by the current loop. If one starts from this definition and try to write it in terms of angular momentum, one will never get a factor of c! | |
| Jul 29, 2012 at 9:27 | history | answered | Siyuan Ren | CC BY-SA 3.0 |