Timeline for Why is not ${(\Lambda^T)^\mu}_\nu = {\Lambda_\nu}^\mu$?
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9 events
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Aug 22, 2017 at 16:06 | history | edited | Qmechanic♦ |
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Apr 30, 2017 at 17:52 | vote | accept | Mikkel Rev | ||
Apr 30, 2017 at 9:51 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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Apr 30, 2017 at 9:50 | answer | added | Qmechanic♦ | timeline score: 12 | |
Apr 29, 2017 at 23:21 | comment | added | Mikkel Rev | @knzhou By your first comment, I believe you confirm that you're puzzled too, correct? Flipping the indecies is exactly what I propose, but that's what the lecture notes do not. | |
Apr 29, 2017 at 23:09 | comment | added | knzhou | The upstairs/downstairs index placement is a red herring that can only add confusion; it's not a 'real' index because $\Lambda$ is not a tensor. | |
Apr 29, 2017 at 23:08 | comment | added | knzhou | I think you're put an extra flip in there somewhere. Just think about it like matrices: $ABC = D$ means $A_{ij} B_{jk} C_{k\ell} = D_{i\ell}$. Therefore $A^T BC = D$ means $B_{jk} A_{ji} C_{k\ell} = D_{i\ell}$ where I used the commutativity of multiplication, and replaced $A_{ij}$ with $A_{ji}$. This is exactly the same as equation (1). | |
Apr 29, 2017 at 22:31 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
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Apr 29, 2017 at 22:18 | history | asked | Mikkel Rev | CC BY-SA 3.0 |