Timeline for Why is kinetic energy not conserved during an inelastic collison?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| May 2, 2017 at 23:25 | answer | added | numberspie | timeline score: -1 | |
| Apr 27, 2017 at 14:51 | answer | added | Michael Seifert | timeline score: 1 | |
| Apr 27, 2017 at 13:44 | history | edited | Qmechanic♦ | CC BY-SA 3.0 |
edited tags; edited title
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| Apr 27, 2017 at 13:16 | comment | added | alephzero | You are mixing up "the real world" with an idealized system consisting of two perfectly rigid bodies. In the real world, the collision can transform some of the mechanical (kinetic) energy into other forms like heat, electromagnetic radiation, etc. If the bodies can deform (and no real-world body is perfectly rigid) some of the KE can end up as internal vibration in the body, not as "movement of its center of mass". In fact the definition of "inelastic collision" is simply that "mechanical energy is not conserved." | |
| Apr 27, 2017 at 10:47 | answer | added | anna v | timeline score: 3 | |
| Apr 27, 2017 at 10:38 | comment | added | Farcher | Duplicate physics.stackexchange.com/q/288835 and physics.stackexchange.com/q/93739 and . . . . . . | |
| Apr 27, 2017 at 10:37 | answer | added | Apoorv | timeline score: 1 | |
| Apr 27, 2017 at 10:36 | comment | added | LM26 | But would that not go against the mathematics which I have presented ? | |
| Apr 27, 2017 at 10:33 | comment | added | Steeven | It doesn't. Some energy is lost to e.g. deforming the material or heat or something else which makes this inelastic | |
| Apr 27, 2017 at 10:28 | history | edited | dmckee --- ex-moderator kitten | CC BY-SA 3.0 |
typeset math; minor blue-pencil work
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| Apr 27, 2017 at 10:23 | history | asked | LM26 | CC BY-SA 3.0 |