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Let me change the person in the chair, for a mass attached to a string. Take a look to escalar definition of angular momentum $L=r\, p = r \, mv$ where $r$ is the string longitude and $p$ is the mass linear momentum. The angular momentum is a conserved cuantity. Then if, the string longitude changes, the linear momentum have to changes too for maintain the angular momentum as at the first. ($\omega = \frac{v}{r}$) The force that you are looking force is exerted by the boy, because he is changing the movement radius thus the centripetal acceleration.

Let me change the person in the chair, for a mass attached to a string. Take a look to escalar definition of angular momentum $L=r\, p = r \, mv$ where $r$ is the string longitude and $p$ is the mass linear momentum. The angular momentum is a conserved cuantity. Then if, the string longitude changes, the linear momentum have to changes too for maintain the angular momentum as at the first. ($\omega = \frac{v}{r}$)

Let me change the person in the chair, for a mass attached to a string. Take a look to escalar definition of angular momentum $L=r\, p = r \, mv$ where $r$ is the string longitude and $p$ is the mass linear momentum. The angular momentum is a conserved cuantity. Then if, the string longitude changes, the linear momentum have to changes too for maintain the angular momentum as at the first. ($\omega = \frac{v}{r}$) The force that you are looking force is exerted by the boy, because he is changing the movement radius thus the centripetal acceleration.

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Let me change the person in the chair, for a mass attached to a string. Take a look to escalar definition of angular momentum $L=r\, p = r \, mv$ where $r$ is the string longitude and $p$ is the mass linear momentum. The angular momentum is a conserved cuantity. Then if, the string longitude changes, the linear momentum have to changes too for maintain the angular momentum as at the first. ($\omega = \frac{v}{r}$)