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Siyuan Ren
Siyuan Ren
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Choose $\alpha$ as the generalized coordinate, so $y_\text{COM}=\frac{1}{2}L \sin\alpha$, and $x_B=L\cos\alpha$.

Then $\delta y_\text{COM}=\frac{1}{2}L \cos\alpha \,\delta\alpha$, and $\delta x_B=L\sin\alpha \,\delta\alpha$$\delta x_B=-L\sin\alpha \,\delta\alpha$. Substitute into the equation.

Choose $\alpha$ as the generalized coordinate, so $y_\text{COM}=\frac{1}{2}L \sin\alpha$, and $x_B=L\cos\alpha$.

Then $\delta y_\text{COM}=\frac{1}{2}L \cos\alpha \,\delta\alpha$, and $\delta x_B=L\sin\alpha \,\delta\alpha$. Substitute into the equation.

Choose $\alpha$ as the generalized coordinate, so $y_\text{COM}=\frac{1}{2}L \sin\alpha$, and $x_B=L\cos\alpha$.

Then $\delta y_\text{COM}=\frac{1}{2}L \cos\alpha \,\delta\alpha$, and $\delta x_B=-L\sin\alpha \,\delta\alpha$. Substitute into the equation.

Source Link
Siyuan Ren
Siyuan Ren
  • 5k
  • 3
  • 26
  • 38

Choose $\alpha$ as the generalized coordinate, so $y_\text{COM}=\frac{1}{2}L \sin\alpha$, and $x_B=L\cos\alpha$.

Then $\delta y_\text{COM}=\frac{1}{2}L \cos\alpha \,\delta\alpha$, and $\delta x_B=L\sin\alpha \,\delta\alpha$. Substitute into the equation.