Timeline for How the useful, unitary "Folding Transform" is applied to a Hamiltonian

9 events

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Jun 11, 2020 at 9:33	history	edited	CommunityBot		Commonmark migration
Apr 22, 2017 at 22:47	vote	accept	JDR
Apr 19, 2017 at 1:58	answer	added	JDR		timeline score: 1
Apr 18, 2017 at 22:22	comment	added	Cosmas Zachos		I stand corrected. Their eqn (15) appears malformed, if one heeds the figure. One would expect the λs to now all be in the fundamental domain, n=1, or whatever. He appears to be transforming the propagators (3) with his operator, not the static hamiltonian you are writing here.
Apr 18, 2017 at 20:39	comment	added	JDR		@CosmasZachos I thought it would simplify to $\lambda$ for a different reason, namely that $\sum_{n_1,\lambda \in n_1, n_2, \lambda \in n_2}e^{i(n_1-n_2) \omega t} \left\| \lambda, n_1 \right\rangle \left\langle \lambda, n_1 \right\| H_0 \left\| \lambda, n_2 \right\rangle \left\langle \lambda, n_2 \right\| = \sum_{n,\lambda \in n} \lambda \left\| \lambda, n \right\rangle \left\langle \lambda, n \right\| $ because of the matrix elements, not the exponential
Apr 18, 2017 at 19:31	comment	added	Cosmas Zachos		U is a Sylvester clock matrix; work out its commutation relations with the original hamiltonian. The are not null.
Apr 18, 2017 at 18:28	history	edited	JDR	CC BY-SA 3.0	added 557 characters in body; edited tags; edited title
Apr 18, 2017 at 15:12	review	First posts
Apr 18, 2017 at 15:13
Apr 18, 2017 at 15:09	history	asked	JDR	CC BY-SA 3.0