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Apr 27, 2017 at 3:01 review First posts
Apr 27, 2017 at 3:20
Apr 17, 2017 at 21:53 comment added Jay N @blue Energy conservation and momentum conservation will give the same result. Differentiating twice equation 1 for one more relation.(note: rate of change of acceleration will be zero for both) Also try rewriting equation one with v of mass m in form of V(x) and V(y) and use constraints relation.
Apr 17, 2017 at 21:40 comment added rob Hi, welcome to Physics.SE. We try to answer conceptual questions without becoming a homework help service; I've edited out your photograph of a "complete solution."
Apr 17, 2017 at 21:39 history edited rob CC BY-SA 3.0
Remove complete answer
Apr 17, 2017 at 21:17 vote accept CommunityBot
Apr 17, 2017 at 21:11 comment added user139621 If those two equations are not sufficient then what other equation do we need in addition to them? (I like your method of solution using forces/acceleration but I wan't to do it using the energy approach).
Apr 17, 2017 at 21:08 comment added Jay N No, without putting values of m & M, the equation 1 & 2 are not sufficient.
Apr 17, 2017 at 21:02 comment added user139621 Ok, I see! In that case are my two equations sufficient to find $dv_2/dt$ without putting any values for $m$ and $M$. I think there are too many variables. Will they all get eliminated?
Apr 17, 2017 at 20:59 comment added Jay N Differentiate h(t) twice for acceleration. Or the given eqn is of form x-x0 = ut +(0.5)at^2(Displacement in uniform accelerated motion)
Apr 17, 2017 at 20:56 history edited Jay N CC BY-SA 3.0
added 103 characters in body
Apr 17, 2017 at 20:56 comment added user139621 Where does the question state that the acceleration of block is $3 m/s^2$ ? It doesn't.
Apr 17, 2017 at 20:53 history answered Jay N CC BY-SA 3.0