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May 29, 2020 at 23:49 comment added Diracology @Krish I just used momentum conservation.
May 29, 2020 at 12:00 comment added Krish How did you derive $v_2=-v_1\frac{m'-m}{m'+m}$ ?
Apr 13, 2017 at 19:46 comment added Michael Seifert @KunalPawar: No electrons or nuclei make contact with each other when two billiard balls collide, either. The forces involved in both cases are the same.
Apr 13, 2017 at 18:01 comment added Shashaank @KunalPawar A collision or crash is an event in which two or more bodies exert forces on each other for a relatively short time. Although the most common colloquial use of the word "collision" refers to incidents in which two or more objects collide, the scientific use of the word "collision" implies nothing about the magnitude of the force.
Apr 13, 2017 at 16:34 comment added Kunal Pawar There is no actual collision taking place is there? The alpha particle never actually touched the nucleus. It just came as close as its energy permitted and turned around (if it were destined for a head-on collision) or just scattered.
Apr 13, 2017 at 15:12 comment added dmckee --- ex-moderator kitten This. Classical scattering theory forces you to understand the nucleus as considerably heavier than the alpha.
Apr 13, 2017 at 12:22 history answered Diracology CC BY-SA 3.0