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Apr 13, 2017 at 12:59 history edited CommunityBot
replaced http://aviation.stackexchange.com/ with https://aviation.stackexchange.com/
Apr 12, 2017 at 8:19 history edited Peter Kämpf CC BY-SA 3.0
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Apr 12, 2017 at 8:14 comment added Peter Kämpf @Crafterguy At higher angle of attack the suction peak on the upper side is higher, meaning more acceleration and, consequently, more deceleration, since the air needs to go back to ambient pressure eventually. The faster air inside the suction peak will experience more friction, frictional energy loss being proportional to speed. So in the deceleration phase the air will eventually not have enough momentum to still move forward when the pressure is increased back to ambient. That is essentially what the answer says already.
Apr 11, 2017 at 22:05 comment added Crafterguy No I read your answer. I just have a question about it. The last comment made it seem like a wanted another answer but, that was not the case. I wrote that comment at like 12pm so I was kind of tired and not thinking clearly
Apr 9, 2017 at 5:41 comment added Peter Kämpf So you think you are entitled to answers to questions which show that you did not read the existing answer?
Apr 9, 2017 at 0:43 comment added Crafterguy I do not see why no one is answering this question or at least commenting. If something is wrong with the question like it don't not show up correctly or something like that please tell me
Apr 9, 2017 at 0:42 comment added Crafterguy "At higher angle of attack the air was accelerated more, so more energy is lost to friction." If the air is moving faster then would'ent it take a longer time to slow down because it has to bleed off more energy.
Apr 6, 2017 at 23:45 comment added Crafterguy Hello? Is anyone going to answer this?
Mar 31, 2017 at 12:33 history answered Peter Kämpf CC BY-SA 3.0