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Jul 16, 2012 at 8:08 comment added Ron Maimon @ArnoldNeumaier: No it isn't. I looked at what Summers says, he just says that the vacuum is entangled with respect to the local observables at two separated regions. For a free field, this is the same as the entanglement when you rotate the unentangled k-state into the x-state field basis. It's a not so enlightening statement.
Jul 16, 2012 at 7:34 history edited Arnold Neumaier CC BY-SA 3.0
added an explanation why Summers' alternative notion ''works''.
Jul 16, 2012 at 7:34 comment added Arnold Neumaier @twistor59: I added a remark at the end to showin which sense one can reconcile the two notions.
Jul 16, 2012 at 7:28 comment added Arnold Neumaier @RonMaimon: But it is what Summers says vacuum entanglement is. As I said, there are multiple notions.
Jul 15, 2012 at 21:34 comment added Ron Maimon This answer is not describing what people mean by vacuum entanglement--- they mean the entaglement between different field states in the Schrodinger wave-functional. This is something which doesn't refer to asymptotic particle states, and you can work it out in free field theory easily.
Jul 15, 2012 at 18:26 comment added twistor59 Thanks, that's very illuminating. So the answer to my original question is "no" it's not possible to phrase the vacuum entanglement referred to by Werner and Summers in conventional ($\mathcal{H}_A \otimes \mathcal{H}_B$) entanglement terms.
Jul 15, 2012 at 17:54 history answered Arnold Neumaier CC BY-SA 3.0