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Timeline for Doppler frequency shift radar

Current License: CC BY-SA 3.0

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Mar 12, 2017 at 15:42 vote accept Corvinus
Mar 12, 2017 at 12:55 answer added DJohnM timeline score: 2
Mar 12, 2017 at 12:48 comment added diracula The two possible answers you gave are however the same to first order, so if you neglected second order effects then they are essentially the same answer. (You might try including relativistic effects to see if they then agree.)
Mar 12, 2017 at 12:40 comment added diracula True, time dilation is a second order effect so you could get the correct first order result by neglecting it. I hadn't considered that, sorry.
Mar 12, 2017 at 12:28 comment added Corvinus @diracula Yes, you're right. I've edited my question and added that the wave is reflected off the car. As for relativistic effects, I know not taking them into account is going to introduce some error but because $v << c$, I suppose that this effect can be neglected.
Mar 12, 2017 at 12:26 history edited Corvinus CC BY-SA 3.0
added 59 characters in body
Mar 12, 2017 at 12:19 comment added diracula If the wave is being reflected off the car you should mention it in the question. Also you've added 'without taking into account relativistic effects', but electromagnetic radiation is relativistic so this would give a (significantly) incorrect answer.
Mar 12, 2017 at 12:12 comment added Corvinus @diracula No. I meant perceived by the radar. The emitted wave is sent how reflects on the car back to the radar. This reflected wave has a different frequency $\omega_r$ than the one that is emitted ($\omega_0$). My question is what is $\omega_r$?
Mar 12, 2017 at 12:10 history edited Corvinus CC BY-SA 3.0
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Mar 12, 2017 at 12:08 comment added diracula Did you mean to instead say 'perceived by the car'? The correct relation is $\omega_r = \left(\frac{1-\beta}{1+\beta}\right)^{\frac{1}{2}} \omega_0$ where $\beta =\frac{v}{c}$ - see here.
Mar 12, 2017 at 10:14 history asked Corvinus CC BY-SA 3.0