Timeline for How to calculate the electric field induced by a changing line current, using simple math?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Feb 24, 2017 at 7:48 | comment | added | Xynon | But the E field is already constant at all times, as long as the inducing current keeps rising at a steady rate. Becuase the induced E field is proportional to the [change in current] / [change in time]. | |
| Feb 24, 2017 at 7:05 | comment | added | Sarthak Sharma | That equation which you derived gives the value of net electric field at any moment in time, maybe calculus can be used to sum all those fields over time. | |
| Feb 24, 2017 at 6:53 | comment | added | MaDrung | I meant in the change of current, not current. Sorry for confusing you. | |
| Feb 24, 2017 at 6:46 | comment | added | MaDrung | If the current in the primary cable is increasing, the direction of induced current in the other wire Will be in the opposite way of which the primary current is inreasing in. If the current stays the same, the current in the other wire Will stop flowing. If the current starts decreasing in the primary wire, it Will start to again flow in the opposite way from which the primary current is decreasing in. So in those 2 cases it Will change direction. So in which ever way the current is changing, the induced current Will be in the opposite way of that current. | |
| Feb 23, 2017 at 17:49 | comment | added | Xynon | And if the current in the primary cable is decreasing, would the induced E field be in the same direction? | |
| Feb 23, 2017 at 11:02 | history | asked | Xynon | CC BY-SA 3.0 |