Skip to main content
6 events
when toggle format what by license comment
Feb 23, 2017 at 23:03 comment added Qmechanic Comment to the post (v2): Note that Grassmann-numbers can be real.
Feb 23, 2017 at 12:22 history edited Qmechanic CC BY-SA 3.0
added 6 characters in body; edited tags
Feb 23, 2017 at 12:21 answer added Qmechanic timeline score: 2
Feb 23, 2017 at 9:12 comment added StrangeField If there is an eigenvactor ${a}$ with $\psi{a} = \lambda_a {a}$ then $\psi^2 {a} = \lambda_a ^2 {a} = 0$. But I'm not sure if there is an eigenvector at all.
Feb 23, 2017 at 9:09 comment added Demosthene What's the eigenvalue of a field operator? Do you consider that $\psi\psi=0$ says something about eigenvalues?
Feb 23, 2017 at 8:53 history asked StrangeField CC BY-SA 3.0