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Yashas
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The only force that acts on the body is only gravitygravitational force, so by. By the time it hits the ground, the force will continue being the gravity force that is F=M.gkeep operating $F=Mg$

You can also see this by calculating the time a body takes to fall from a height h $h$: h=v0.t+0.5.g.t^2$$h=v_ot + \frac{1}{2}gt^2$$ so you have v0=0$v_0=0$ and t= √(2h/g)$t= \sqrt{\frac{2h}{g}}$

Now replace it onin your ecuationequation a have that F=M.g$F=Mg$

The force that acts on the body is only gravity force, so by the time it hits the ground the force will continue being the gravity force that is F=M.g

You can also see this by calculating the time a body takes to fall from a height h : h=v0.t+0.5.g.t^2 so you have v0=0 and t= √(2h/g)

Now replace it on your ecuation a have that F=M.g

The only force that acts on the body is gravitational force. By the time it hits the ground, the force will keep operating $F=Mg$

You can also see this by calculating the time a body takes to fall from a height $h$: $$h=v_ot + \frac{1}{2}gt^2$$ so you have $v_0=0$ and $t= \sqrt{\frac{2h}{g}}$

Now replace it in your equation a have that $F=Mg$

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The force that acts on the body is only gravity force, so by the time it hits the ground the force will continue being the gravity force that is F=M.g

You can also see this by calculating the time a body takes to fall from a height h : h=v0.t+0.5.g.t^2 so you have v0=0 and t= √(2h/g)

Now replace it on your ecuation a have that F=M.g