I have been struggling with problem for a while :

Consider a body of mass $M$ released from a height of $h$ meters above the ground. With what amount of Force will it hit the ground ?

My Attempt :

I assume that air-resistance is non-existent and that $h$ is small enough so that the change in $g$ (Acceleration due to Gravity) can be ingnored.

Let the body hit the ground with velocity $v$. As its initial velocity is $0$, with a little bit of calculations, it can be found that $v=\sqrt{2gh}$. So, the momentum of the body on striking the ground $=M\sqrt{2gh}$. But the problem here is that the time for which the body is in contact with the ground is not specifically given. If we assume it to be $t$, the force exerted by the body comes out to be $M\dfrac{\sqrt{2gh}}{t}$.

Is there any way of calculating the Force without including the time of contact?

I know that $|F|=\dfrac{dp}{dt}$, but calculus can not be used here since we are not given $p$ as a function of time. ($p$ means the linear momentum of the body.)

I have been struggling with problem for a while :

Consider a body of mass $M$ released from a height of $h$ meters above the ground. With what amount of Force will it hit the ground ?

My Attempt :

I assume that air-resistance is non-existent and that $h$ is small enough so that the change in $g$ (Acceleration due to Gravity) can be ignored.

Let the body hit the ground with velocity $v$. As its initial velocity is $0$, with a little bit of calculations, it can be found that $v=\sqrt{2gh}$. So, the linear momentum(p) of the body on striking the ground $=Mv=M\sqrt{2gh}$. But the problem here is that the time for which the body is in contact with the ground is not specifically given. If we assume it to be $\Delta t$, the force exerted by the body comes out to be $\dfrac{\Delta p}{\Delta t}=M\dfrac{\sqrt{2gh}}{t}$.

Is there any way of calculating the Force without including the time of contact?

I know that $|F|=\dfrac{dp}{dt}$, but calculus can not be used here since we are not given $p$ as a function of time.

I have been struggling with problem for a while :

Consider a body of mass $M$ released from a height of $h$ meters above the ground. With what amount of Force will it hit the ground ?

My Attempt :

I assume that air-resistance is non-existent and that $h$ is small enough so that the change in $g$ (Acceleration due to Gravity) can be ingnored.

Let the body hit the ground with velocity $v$. As its initial velocity is $0$, with a little bit of calculations, it can be found that $v=\sqrt{2gh}$. So, the momentum of the body on striking the ground $=M\sqrt{2gh}$. But the problem here is that the time for which the body is in contact with the ground is not specifically given. If we assume it to be $t$, the force exerted by the body comes out to be $M\dfrac{\sqrt{2gh}}{t}$.

Is there any way of calculating the Force without including the time of contact  ?

I know that $|F|=\dfrac{dp}{dt}$, but calculus can not be used here since we are not given $p$ as a function of time. ($p$ means the linear momentum of the body.)

Thanks in Advance ! :-)

I have been struggling with problem for a while :

Consider a body of mass $M$ released from a height of $h$ meters above the ground. With what amount of Force will it hit the ground ?

My Attempt :

I assume that air-resistance is non-existent and that $h$ is small enough so that the change in $g$ (Acceleration due to Gravity) can be ingnored.

Let the body hit the ground with velocity $v$. As its initial velocity is $0$, with a little bit of calculations, it can be found that $v=\sqrt{2gh}$. So, the momentum of the body on striking the ground $=M\sqrt{2gh}$. But the problem here is that the time for which the body is in contact with the ground is not specifically given. If we assume it to be $t$, the force exerted by the body comes out to be $M\dfrac{\sqrt{2gh}}{t}$.

Is there any way of calculating the Force without including the time of contact?

I know that $|F|=\dfrac{dp}{dt}$, but calculus can not be used here since we are not given $p$ as a function of time. ($p$ means the linear momentum of the body.)