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Feb 3, 2020 at 17:46 comment added ACuriousMind @Peter4075 $L = \vec r \wedge \vec p$ was a bad choice of notation on my part. What I really meant was to take the wedge of the duals of the vector fields $\vec r(\vec r)$ and $\vec p(\vec r)$ (i.e. $x\mathrm{d}x + y \mathrm{d}y + z \mathrm{d}z$ and $p_x \mathrm{d}x + p_y \mathrm{d}y + p_z \mathrm{d}z$).
Feb 3, 2020 at 8:47 comment added Peter4075 Naive question, but how can the exterior product of two vectors $L=\vec{r}\wedge\vec{p}$ be a 2-form? I thought a 2-form had to contains things like (in Cartesian coordinates) $dy\wedge dz$, $dz\wedge dx$ and $dx\wedge dy$.
Apr 3, 2019 at 14:35 review Suggested edits
Apr 3, 2019 at 15:10
Apr 13, 2017 at 12:40 history edited CommunityBot
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Feb 20, 2017 at 3:10 vote accept Akerai
Feb 19, 2017 at 0:47 history answered ACuriousMind CC BY-SA 3.0